We can solve this problem using algebra. Let the tens digit be x and the units digit be y. Then, we have:
10x + y = xy + 18 (since the product of the digits is 18)
10x + y - 27 = 10y + x (since 27 is subtracted from the number and the digits are interchanged)
Simplifying the second equation, we get:
9x - 9y = 27
x - y = 3
Solving for x and y, we get:
y = x - 3
9x - 9(x - 3) = 27
x = 6
Therefore, y = 3, and the number is 63.
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